Today’s ACT question of the day is an algebra question that’s great practice for either test.  The question:

For all x > 0, simplifies to:

Let’s knock out the numerator first.

We can pull out a 2 like so: 2(x^2 + 7x + 12)

Then, we can factor the part that’s left in the parentheses.  4 and 3 are factors of 12 that sum to 7, and everything is positive, so the numerator becomes: 2(x + 3)(x + 4)

Putting the fraction back together, we get: 2(x + 3)(x + 4)/(x + 4)

(x+4)/(x+4) = 1, so we can remove (x + 4) from the numerator and denominator.  This leaves 2(x + 3) , or choice C.